What is the derivative of f(x)=(8x)/(e^x) ?

The derivative of f(x)=(8x)/(e^x) is (8(1-x))/(e^x)

What is the first derivative of f(x)=(8x)/(e^x) ?

The first derivative of f(x)=(8x)/(e^x) is (8(1-x))/(e^x)

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derivative of

f (x) = \frac{8 x}{e ^{x}}

\frac{8 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{8 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 8 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 8 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

8 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{8 ( 1 - x )}{e ^{x}}

= \frac{8 ( 1 - x )}{e ^{x}}

\frac{d x}{d t} = 5 x (7 - x)

cos (x + y) d y = sin (x + y) d x

\int \frac{1}{( 625 + x ^{2} ) ^{\frac{3}{2}}} d x

\int 2 + 2 cos (θ) d θ

y^{3} - (10 x + 2) + 3 x y^{2} y^{^{'}} = 0

What is the derivative of f(x)=(8x)/(e^x) ?
The derivative of f(x)=(8x)/(e^x) is (8(1-x))/(e^x)
What is the first derivative of f(x)=(8x)/(e^x) ?
The first derivative of f(x)=(8x)/(e^x) is (8(1-x))/(e^x)