What is the derivative of y= 5/(2x^3) ?

The derivative of y= 5/(2x^3) is -(15)/(2x^4)

What is the first derivative of y= 5/(2x^3) ?

The first derivative of y= 5/(2x^3) is -(15)/(2x^4)

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derivative of

y = \frac{5}{2 x ^{3}}

- \frac{15}{2 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{5}{2 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{5}{2} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{5}{2} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{5}{2} (- 3 x^{- 3 - 1})

Simplify

\frac{5}{2} (- 3 x^{- 3 - 1}) : - \frac{15}{2 x ^{4}}

= - \frac{15}{2 x ^{4}}

\frac{\partial}{\partial x} (e^{- (\frac{x ^{2} + y ^{2}}{2})})

\int_{2}^{6} \frac{x}{x ^{2} + 6 x + 13} d x

\int - \frac{1}{x ^{2} + 1} d x

y = x^{7}, - 2, 3

t \to 0 lim (\frac{8}{t} - \frac{8}{t ^{2} + t})

What is the derivative of y= 5/(2x^3) ?
The derivative of y= 5/(2x^3) is -(15)/(2x^4)
What is the first derivative of y= 5/(2x^3) ?
The first derivative of y= 5/(2x^3) is -(15)/(2x^4)