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Popular >

y^'+6y=1,y(0)=1

Solution

y^{^{'}} + 6 y = 1, y (0) = 1

Solution

y = \frac{1}{6} + \frac{5}{6 e ^{6 t}}

Solution steps

y^{'} (t) + 6 y = 1

Solve linear ODE:

y = \frac{1}{6} + \frac{5}{6 e ^{6 t}}

y = \frac{1}{6} + \frac{5}{6 e ^{6 t}}

Graph

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16 y^{^{''}} + 72 y^{^{'}} + 87 y = 0, y (0) = 2, y^{^{'}} (0) = 4

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\int \frac{( ln ( x ) ) ^{18}}{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+6y=1,y(0)=1 ?
The solution for y^'+6y=1,y(0)=1 is y= 1/6+5/(6e^{6t)}