What is the derivative of 2x^2-x^3 ?

The derivative of 2x^2-x^3 is 4x-3x^2

What is the first derivative of 2x^2-x^3 ?

The first derivative of 2x^2-x^3 is 4x-3x^2

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\frac{d}{d x} (2 x^{2} - x^{3})

4 x - 3 x^{2}

Solution steps

\frac{d}{d x} (2 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 4 x - 3 x^{2}

\int (x^{2} - 5)^{2} 0.2 x d x

\int_{6}^{7} \frac{x}{x - 6} d x

\int (3 x + 2) d x

\int - 1 e^{x} d x

\int \frac{x ^{3}}{3} + 2 x - 5 d x

What is the derivative of 2x^2-x^3 ?
The derivative of 2x^2-x^3 is 4x-3x^2
What is the first derivative of 2x^2-x^3 ?
The first derivative of 2x^2-x^3 is 4x-3x^2