What is the tangent of g(x)=sqrt(5x+20),\at x=1 ?

The tangent of g(x)=sqrt(5x+20),\at x=1 is y= 1/2 x+9/2

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tangent of g(x)=sqrt(5x+20),\at x=1

tangent of

g (x) = 5 x + 20, at x = 1

y = \frac{1}{2} x + \frac{9}{2}

Solution steps

Find the tangent point:

(1, 5)

Find the slope of

g (x) = 5 x + 20 : \frac{d g ( x )}{d x} = \frac{5}{2 5 x + 20}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(1, 5) : y = \frac{1}{2} x + \frac{9}{2}

y = \frac{1}{2} x + \frac{9}{2}

4 x + 3

y^{^{''}} - 6 y^{^{'}} + 9 y = e^{3 x}

x \to 3 lim (x 25 - x^{3})

\frac{d}{d x} (3 - 2 sin (2 x - \frac{π}{4}))

\int e^{x} 3 x^{2} d x

What is the tangent of g(x)=sqrt(5x+20),\at x=1 ?
The tangent of g(x)=sqrt(5x+20),\at x=1 is y= 1/2 x+9/2