What is the derivative of x^2+sin(2x) ?

The derivative of x^2+sin(2x) is 2x+cos(2x)*2

What is the first derivative of x^2+sin(2x) ?

The first derivative of x^2+sin(2x) is 2x+cos(2x)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + sin (2 x))

2 x + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (x^{2} + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 x + cos (2 x) \cdot 2

\frac{d}{d x} (\frac{3 ( 2 x + 1 )}{6 x + 6 x ^{2}})

\frac{d y}{d x} = sin (3 y) ln (x)

sin (x) + \frac{7}{2} cot (x)

\int y e^{- x y} d x

f (x) = \frac{x - 2}{x ^{2}}

What is the derivative of x^2+sin(2x) ?
The derivative of x^2+sin(2x) is 2x+cos(2x)*2
What is the first derivative of x^2+sin(2x) ?
The first derivative of x^2+sin(2x) is 2x+cos(2x)*2