What is the solution for f^'(x)=3cos(x)+4(-sin(x)) ?

The solution for f^'(x)=3cos(x)+4(-sin(x)) is f(x)=3sin(x)+4cos(x)+c_{1}

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f^'(x)=3cos(x)+4(-sin(x))

f^{^{'}} (x) = 3 cos (x) + 4 (- sin (x))

f (x) = 3 sin (x) + 4 cos (x) + c_{1}

Solution steps

f^{'} (x) = 3 cos (x) + 4 (- sin (x))

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 3 cos (x) + 4 (- sin (x)) d x

\int 3 cos (x) + 4 (- sin (x)) d x = 3 sin (x) + 4 cos (x) + c_{1}

f (x) = 3 sin (x) + 4 cos (x) + c_{1}

x \to 0 + lim (\frac{2}{ln ( x )})

\frac{d}{d x} (8 x^{2} ln (8 x))

\frac{1}{s ^{4} + 1}

\int_{0}^{\frac{π}{2}} cos (2 x) d x

\frac{d}{d x} (\frac{1}{4} cos (\frac{x}{4}))

What is the solution for f^'(x)=3cos(x)+4(-sin(x)) ?
The solution for f^'(x)=3cos(x)+4(-sin(x)) is f(x)=3sin(x)+4cos(x)+c_{1}