What is (\partial)/(\partial u)(3yuxuv^3-2) ?

The answer to (\partial)/(\partial u)(3yuxuv^3-2) is 6yuxv^3

Popular >

(\partial)/(\partial u)(3yuxuv^3-2)

\frac{\partial}{\partial u} (3 y uxu v^{3} - 2)

6 y ux v^{3}

Solution steps

\frac{\partial}{\partial u} (3 y uxu v^{3} - 2)

Simplify

3 y uxu v^{3} - 2 : 3 y u^{2} x v^{3} - 2

= \frac{\partial}{\partial u} (3 y u^{2} x v^{3} - 2)

Treat

y, x, v

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (3 y u^{2} x v^{3}) - \frac{\partial}{\partial u} (2)

\frac{\partial}{\partial u} (3 y u^{2} x v^{3}) = 6 y x v^{3} u

\frac{\partial}{\partial u} (2) = 0

= 6 y x v^{3} u - 0

Simplify

= 6 y ux v^{3}

\int \frac{1}{100 - 2 x} d x

\frac{\partial}{\partial x} ((3 x^{2} + 4)^{3})

\frac{d y}{d x}, sec (9 x + 2) + 6 y^{2} = 42

f (x) = 3 x^{3} - x^{2} + 4, at x = 1

\frac{d}{d x} (e^{4 x^{2}} csc (5 x))

What is (\partial)/(\partial u)(3yuxuv^3-2) ?
The answer to (\partial)/(\partial u)(3yuxuv^3-2) is 6yuxv^3