What is the derivative of sin(-2x) ?

The derivative of sin(-2x) is -cos(2x)*2

What is the first derivative of sin(-2x) ?

The first derivative of sin(-2x) is -cos(2x)*2

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derivative of

sin (- 2 x)

- cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (- 2 x))

Simplify

sin (- 2 x) : - sin (2 x)

= \frac{d}{d x} (- sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - cos (2 x) \cdot 2

\int \frac{1}{10 ( x ^{2} + 1 )} d x

(2 x - 7)^{- 1} (x + 5)

\frac{d}{d x} (- 4 cot (x))

(1 + x^{2})^{^{'}}

x \to 1 lim (x^{3} + 2 x^{2} - x - 2)

What is the derivative of sin(-2x) ?
The derivative of sin(-2x) is -cos(2x)*2
What is the first derivative of sin(-2x) ?
The first derivative of sin(-2x) is -cos(2x)*2