What is the derivative of x^3-5x^2+4x-20-5e^{3x} ?

The derivative of x^3-5x^2+4x-20-5e^{3x} is 3x^2-10x-15e^{3x}+4

What is the first derivative of x^3-5x^2+4x-20-5e^{3x} ?

The first derivative of x^3-5x^2+4x-20-5e^{3x} is 3x^2-10x-15e^{3x}+4

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\frac{d}{d x} (x^{3} - 5 x^{2} + 4 x - 20 - 5 e^{3 x})

3 x^{2} - 10 x - 15 e^{3 x} + 4

Solution steps

\frac{d}{d x} (x^{3} - 5 x^{2} + 4 x - 20 - 5 e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (20) - \frac{d}{d x} (5 e^{3 x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (20) = 0

\frac{d}{d x} (5 e^{3 x}) = 15 e^{3 x}

= 3 x^{2} - 10 x + 4 - 0 - 15 e^{3 x}

Simplify

= 3 x^{2} - 10 x - 15 e^{3 x} + 4

\frac{d}{d t} (tan (cos (2 t)))

\frac{d}{d x} (x^{5} + 2 x^{3} - x^{2})

\frac{d}{d x} (2 + cot^{2} (x))

x^{2} - 5 x + 1, (- 3, 6)

\int \frac{1}{( sin ( x ) ) ^{5} ( cos ( x ) ) ^{5}} d x

What is the derivative of x^3-5x^2+4x-20-5e^{3x} ?
The derivative of x^3-5x^2+4x-20-5e^{3x} is 3x^2-10x-15e^{3x}+4
What is the first derivative of x^3-5x^2+4x-20-5e^{3x} ?
The first derivative of x^3-5x^2+4x-20-5e^{3x} is 3x^2-10x-15e^{3x}+4