What is the derivative of 2x^2-2x ?

The derivative of 2x^2-2x is 4x-2

What is the first derivative of 2x^2-2x ?

The first derivative of 2x^2-2x is 4x-2

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derivative of

2 x^{2} - 2 x

4 x - 2

Solution steps

\frac{d}{d x} (2 x^{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2 x) = 2

= 4 x - 2

\int 15 arctan (x) d x

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\frac{\partial}{\partial x} (- y^{3} - x)

\int sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) d x

\frac{e ^{- 3 s}}{s ^{2} + 6 s + 13}

What is the derivative of 2x^2-2x ?
The derivative of 2x^2-2x is 4x-2
What is the first derivative of 2x^2-2x ?
The first derivative of 2x^2-2x is 4x-2