What is the solution for (dy)/(dt)+3y=13sin(2t) ?

The solution for (dy)/(dt)+3y=13sin(2t) is y=-2cos(2t)+3sin(2t)+(c_{1})/(e^{3t)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+3y=13sin(2t)

\frac{d y}{d t} + 3 y = 13 sin (2 t)

y = - 2 cos (2 t) + 3 sin (2 t) + \frac{c _{1}}{e ^{3 t}}

Solution steps

\frac{d y}{d t} + 3 y = 13 sin (2 t)

Solve linear ODE:

y = - 2 cos (2 t) + 3 sin (2 t) + \frac{c _{1}}{e ^{3 t}}

y = - 2 cos (2 t) + 3 sin (2 t) + \frac{c _{1}}{e ^{3 t}}

\int \frac{2 x + 1}{x ( x + 2 ) ^{3}} d x

2 x y d x + (x^{2} - y) d y = 0

\frac{\partial}{\partial x} (\frac{64}{x ^{2}})

\frac{\partial}{\partial x} (ln (1 + x^{2}))

\int (1 - x) e^{- x} d x

What is the solution for (dy)/(dt)+3y=13sin(2t) ?
The solution for (dy)/(dt)+3y=13sin(2t) is y=-2cos(2t)+3sin(2t)+(c_{1})/(e^{3t)}