What is (\partial)/(\partial y)(y+6xy^2) ?

The answer to (\partial)/(\partial y)(y+6xy^2) is 1+12xy

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(\partial)/(\partial y)(y+6xy^2)

\frac{\partial}{\partial y} (y + 6 x y^{2})

1 + 12 x y

Solution steps

\frac{\partial}{\partial y} (y + 6 x y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (6 x y^{2})

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (6 x y^{2}) = 12 x y

= 1 + 12 x y

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f (x) = \frac{2}{x}

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\int tan (x) (sec (x))^{2} d x

cos^{2} (x)

What is (\partial)/(\partial y)(y+6xy^2) ?
The answer to (\partial)/(\partial y)(y+6xy^2) is 1+12xy