What is the derivative of (x^2+8^4) ?

The derivative of (x^2+8^4) is 8x(x^2+8)^3

What is the first derivative of (x^2+8^4) ?

The first derivative of (x^2+8^4) is 8x(x^2+8)^3

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\frac{d}{d x} ((x^{2} + 8)^{4})

8 x (x^{2} + 8)^{3}

Solution steps

\frac{d}{d x} ((x^{2} + 8)^{4})

Apply the chain rule:

4 (x^{2} + 8)^{3} \frac{d}{d x} (x^{2} + 8)

= 4 (x^{2} + 8)^{3} \frac{d}{d x} (x^{2} + 8)

\frac{d}{d x} (x^{2} + 8) = 2 x

= 4 (x^{2} + 8)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} + 8)^{3}

f (x) = arctan (3 x)

\int \frac{cos ( x )}{sin ^{16} ( x )} d x

\frac{x}{x + 7}

n = 0 \sum \infty \frac{1}{( 2 n + 1 )}

\frac{d}{d x} (1 - e^{c o s (1 - x^{2})})

What is the derivative of (x^2+8^4) ?
The derivative of (x^2+8^4) is 8x(x^2+8)^3
What is the first derivative of (x^2+8^4) ?
The first derivative of (x^2+8^4) is 8x(x^2+8)^3