What is the derivative of x^3-3x+4 ?

The derivative of x^3-3x+4 is 3x^2-3

What is the first derivative of x^3-3x+4 ?

The first derivative of x^3-3x+4 is 3x^2-3

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\frac{d}{d x} (x^{3} - 3 x + 4)

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

\frac{\partial}{\partial y} (x cos (\frac{y}{z}))

\int \frac{1}{cos ( x ) sin ( x )} d x

\frac{y ^{^{'}}}{3} = x^{2} y, y (0) = - 8

x \frac{d x}{d t} + b t = 0

\frac{\partial}{\partial x} (2 y cos^{2} (x))

What is the derivative of x^3-3x+4 ?
The derivative of x^3-3x+4 is 3x^2-3
What is the first derivative of x^3-3x+4 ?
The first derivative of x^3-3x+4 is 3x^2-3