What is the solution for 4t(dy)/(dt)+y=t^2 ?

The solution for 4t(dy)/(dt)+y=t^2 is y=(t^2)/9+(c_{1})/(\sqrt[4]{t)}

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4t(dy)/(dt)+y=t^2

4 t \frac{d y}{d t} + y = t^{2}

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

Solution steps

4 t \frac{d y}{d t} + y = t^{2}

Solve linear ODE:

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

y = \frac{t ^{2}}{9} + \frac{c _{1}}{4 t}

f (x) = 72 x^{3} (3 x^{4} + 7)^{5}

\frac{d y}{d x} = \frac{y}{2 x}

f (x) = \frac{x}{4 x + 5}

n = 1 \sum \infty \frac{8}{n ^{3}}

\frac{d}{d x} (1 - 3 x^{2} + y^{2})

What is the solution for 4t(dy)/(dt)+y=t^2 ?
The solution for 4t(dy)/(dt)+y=t^2 is y=(t^2)/9+(c_{1})/(\sqrt[4]{t)}