What is the derivative of f(x)=(-x^2+4)^2 ?

The derivative of f(x)=(-x^2+4)^2 is -4x(-x^2+4)

What is the first derivative of f(x)=(-x^2+4)^2 ?

The first derivative of f(x)=(-x^2+4)^2 is -4x(-x^2+4)

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derivative of

f (x) = (- x^{2} + 4)^{2}

- 4 x (- x^{2} + 4)

Solution steps

\frac{d}{d x} ((- x^{2} + 4)^{2})

Apply the chain rule:

2 (- x^{2} + 4) \frac{d}{d x} (- x^{2} + 4)

= 2 (- x^{2} + 4) \frac{d}{d x} (- x^{2} + 4)

\frac{d}{d x} (- x^{2} + 4) = - 2 x

= 2 (- x^{2} + 4) (- 2 x)

Simplify

= - 4 x (- x^{2} + 4)

y = \frac{2}{x - 2} (4.1)

x \to 0 + lim ((2 x)^{5 x})

\int \frac{1}{y ^{2}} d y

x \to 3 lim (\frac{8}{x - 3})

- x^{2} + 4 (x)

What is the derivative of f(x)=(-x^2+4)^2 ?
The derivative of f(x)=(-x^2+4)^2 is -4x(-x^2+4)
What is the first derivative of f(x)=(-x^2+4)^2 ?
The first derivative of f(x)=(-x^2+4)^2 is -4x(-x^2+4)