What is the tangent of y=12(x-1/x)^2,\at x=2 ?

The tangent of y=12(x-1/x)^2,\at x=2 is y=45x-63

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=12(x-1/x)^2,\at x=2

tangent of

y = 12 (x - \frac{1}{x})^{2}, at x = 2

y = 45 x - 63

Solution steps

Find the tangent point:

(2, 27)

Find the slope of

y = 12 (x - \frac{1}{x})^{2} : \frac{d y}{d x} = 12 (2 x - \frac{2}{x ^{3}})

Compute the slope of

y = 12 (x - \frac{1}{x})^{2}

x = 2 : m = 45

Find the line with slope m=

45

and passing through

(2, 27) : y = 45 x - 63

y = 45 x - 63

y = 4 x cos (x^{2})

\int (2 e^{9 x}) d x

\frac{d}{d x} (\frac{( x - 1 )}{( x - 2 )})

\int x^{5} e^{3 x} d x

f (x) = (x + 3)^{2}

What is the tangent of y=12(x-1/x)^2,\at x=2 ?
The tangent of y=12(x-1/x)^2,\at x=2 is y=45x-63