What is area y= 3/x ,y= 3/(x^2),x=5 ?

The answer to area y= 3/x ,y= 3/(x^2),x=5 is 3ln(5)-12/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y= 3/x ,y= 3/(x^2),x=5

area

y = \frac{3}{x}, y = \frac{3}{x ^{2}}, x = 5

3 ln (5) - \frac{12}{5}

Decimal

2.42831 \dots

Solution steps

Apply the area formula:

\int_{1}^{5} \frac{3}{x} - \frac{3}{x ^{2}} d x

Solve

\int_{1}^{5} \frac{3}{x} - \frac{3}{x ^{2}} d x : 3 ln (5) - \frac{12}{5}

The area is:

= 3 ln (5) - \frac{12}{5}

\int \frac{sec ^{2} ( x )}{tan ^{2} ( x ) - 1} d x

x \to 0 lim (csc (x) + cot (x))

f (x) = 2 x^{3} - 2 x^{2} + 8, (3, 44)

y = (x - 1)^{\frac{3}{2}} + \frac{e ^{x - 2}}{2}

\frac{d}{d t} (t^{2} + 4)

What is area y= 3/x ,y= 3/(x^2),x=5 ?
The answer to area y= 3/x ,y= 3/(x^2),x=5 is 3ln(5)-12/5