What is the derivative of 1/2 t^2-6t+23 ?

The derivative of 1/2 t^2-6t+23 is t-6

What is the first derivative of 1/2 t^2-6t+23 ?

The first derivative of 1/2 t^2-6t+23 is t-6

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derivative of

\frac{1}{2} t^{2} - 6 t + 23

t - 6

Solution steps

\frac{d}{d t} (\frac{1}{2} t^{2} - 6 t + 23)

Simplify

\frac{1}{2} t^{2} - 6 t + 23 : \frac{t ^{2}}{2} - 6 t + 23

= \frac{d}{d t} (\frac{t ^{2}}{2} - 6 t + 23)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{t ^{2}}{2}) - \frac{d}{d t} (6 t) + \frac{d}{d t} (23)

\frac{d}{d t} (\frac{t ^{2}}{2}) = t

\frac{d}{d t} (6 t) = 6

\frac{d}{d t} (23) = 0

= t - 6 + 0

Simplify

= t - 6

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What is the derivative of 1/2 t^2-6t+23 ?
The derivative of 1/2 t^2-6t+23 is t-6
What is the first derivative of 1/2 t^2-6t+23 ?
The first derivative of 1/2 t^2-6t+23 is t-6