What is taylor [(z-1)^3(z+1)^2]-1 ?

The answer to taylor [(z-1)^3(z+1)^2]-1 is -2+z+2z^2-2z^3-z^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor [(z-1)^3(z+1)^2]-1

taylor

[(z - 1)^{3} (z + 1)^{2}] - 1

- 2 + z + 2 z^{2} - 2 z^{3} - z^{4}

Solution steps

Apply the Taylor Formula

= - 2 + \frac{\frac{d}{d z} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] - 1 ) ( 0 )}{1 !} z + \frac{\frac{d ^{2}}{d z ^{2}} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] - 1 ) ( 0 )}{2 !} z^{2} + \frac{\frac{d ^{3}}{d z ^{3}} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] - 1 ) ( 0 )}{3 !} z^{3} + \dots

Evaluate Derivatives

= - 2 + \frac{1}{1 !} z + \frac{4}{2 !} z^{2} + \frac{- 12}{3 !} z^{3} + \frac{- 24}{4 !} z^{4}

Refine

= - 2 + z + 2 z^{2} - 2 z^{3} - z^{4}

\int \frac{t ^{2} - 3}{- t ^{3} + 9 t + 1} d t

3 x

\frac{d}{d x} (co x)

\int \frac{x ^{3} + 1}{3 x ^{2}} d x

\frac{\partial}{\partial x} (8 x cos (5 x y))

What is taylor [(z-1)^3(z+1)^2]-1 ?
The answer to taylor [(z-1)^3(z+1)^2]-1 is -2+z+2z^2-2z^3-z^4