What is the d/(dt)(1-|t^3|) ?

The d/(dt)(1-|t^3|) is -(3t^5)/(|t^3|)

What is the first d/(dt)(1-|t^3|) ?

The first d/(dt)(1-|t^3|) is -(3t^5)/(|t^3|)

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\frac{d}{d t} (1 - t^{3})

- \frac{3 t ^{5}}{∣ t ^{3} ∣}

Solution steps

\frac{d}{d t} (1 - t^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d}{d t} (t^{3})

\frac{d}{d t} (1) = 0

\frac{d}{d t} (t^{3}) = \frac{3 t ^{5}}{∣ t ^{3} ∣}

= 0 - \frac{3 t ^{5}}{∣ t ^{3} ∣}

Simplify

= - \frac{3 t ^{5}}{∣ t ^{3} ∣}

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What is the d/(dt)(1-|t^3|) ?
The d/(dt)(1-|t^3|) is -(3t^5)/(|t^3|)
What is the first d/(dt)(1-|t^3|) ?
The first d/(dt)(1-|t^3|) is -(3t^5)/(|t^3|)