What is (\partial)/(\partial x)(sin(z^3)cos(xy)) ?

The answer to (\partial)/(\partial x)(sin(z^3)cos(xy)) is -ysin(xy)sin(z^3)

Popular >

(\partial)/(\partial x)(sin(z^3)cos(xy))

\frac{\partial}{\partial x} (sin (z^{3}) cos (x y))

- y sin (x y) sin (z^{3})

Solution steps

\frac{\partial}{\partial x} (sin (z^{3}) cos (x y))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (z^{3}) \frac{\partial}{\partial x} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{\partial}{\partial x} (x y)

= - sin (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= sin (z^{3}) (- sin (x y) y)

Simplify

= - y sin (x y) sin (z^{3})

\int \frac{x}{( x ^{2} + 4 x + 5 ) ^{2}} d x

x^{^{''}} + 3 x^{^{'}} + 4 x = 0

\frac{d}{d x} (x^{2} + y^{4})

f (x) = \frac{2 x - 1}{x + 7}, at x = 2

f (x) = \frac{1}{2 x}, at x = 100

What is (\partial)/(\partial x)(sin(z^3)cos(xy)) ?
The answer to (\partial)/(\partial x)(sin(z^3)cos(xy)) is -ysin(xy)sin(z^3)