What is (\partial)/(\partial z)(z^2+x^2) ?

The answer to (\partial)/(\partial z)(z^2+x^2) is 2z

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(\partial)/(\partial z)(z^2+x^2)

\frac{\partial}{\partial z} (z^{2} + x^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (z^{2} + x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (z^{2}) + \frac{\partial}{\partial z} (x^{2})

\frac{\partial}{\partial z} (z^{2}) = 2 z

\frac{\partial}{\partial z} (x^{2}) = 0

= 2 z + 0

Simplify

= 2 z

\int e^{- x^{2}} x d x

\frac{d}{d x} (- cos (3 x) 3)

f (x) = a^{2} + cos^{2} (x)

\int e^{y^{2}} y^{3} d y

(7 x + 6)^{2}

What is (\partial)/(\partial z)(z^2+x^2) ?
The answer to (\partial)/(\partial z)(z^2+x^2) is 2z