What is laplacetransform cos(t+1) ?

The answer to laplacetransform cos(t+1) is (cos(1)s-sin(1))/(s^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform cos(t+1)

laplace transform

cos (t + 1)

\frac{cos ( 1 ) s - sin ( 1 )}{s ^{2} + 1}

Solution steps

L {cos (t + 1)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (t + 1)} = \frac{s cos ( 1 ) - 1 \cdot sin ( 1 )}{s ^{2} + 1 ^{2}}

= \frac{s cos ( 1 ) - 1 \cdot sin ( 1 )}{s ^{2} + 1 ^{2}}

= \frac{cos ( 1 ) s - sin ( 1 )}{s ^{2} + 1}

\int \frac{x ^{2} + x}{x ^{2} + x + 1} d x

\int \frac{1}{7 - 4 x} d x

y = e^{- 11 x}

n = 1 \sum \infty n^{3}

\frac{d x}{d t} = 3 t^{2}

What is laplacetransform cos(t+1) ?
The answer to laplacetransform cos(t+1) is (cos(1)s-sin(1))/(s^2+1)