What is area y=e^x,y=7e^{-x},x=0 ?

The answer to area y=e^x,y=7e^{-x},x=0 is -2sqrt(7)+8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=7e^{-x},x=0

area

y = e^{x}, y = 7 e^{- x}, x = 0

- 27 + 8

Decimal

2.70849 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{l n ( 7 )}{2}} e^{x} - 7 e^{- x} d x

Solve

\int_{0}^{\frac{l n ( 7 )}{2}} e^{x} - 7 e^{- x} d x : - 27 + 8

The area is:

= - 27 + 8

\int ln (x + x^{2} - 1) d x

y^{^{'}} = - 100 y + 101 cos (t) + 99 sin (t), y (0) = 1

\int (\frac{1}{x} - \frac{2}{9 x ^{2} + 1}) d x

\frac{d}{d x} ((5 x + 1)^{3})

(9.1) (6.5)

What is area y=e^x,y=7e^{-x},x=0 ?
The answer to area y=e^x,y=7e^{-x},x=0 is -2sqrt(7)+8