What is the derivative of 2sec(x+cot(x)) ?

The derivative of 2sec(x+cot(x)) is 2sec(x)tan(x)-csc^2(x)

What is the first derivative of 2sec(x+cot(x)) ?

The first derivative of 2sec(x+cot(x)) is 2sec(x)tan(x)-csc^2(x)

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\frac{d}{d x} (2 sec (x) + cot (x))

2 sec (x) tan (x) - csc^{2} (x)

Solution steps

\frac{d}{d x} (2 sec (x) + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sec (x)) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (2 sec (x)) = 2 sec (x) tan (x)

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 2 sec (x) tan (x) - csc^{2} (x)

\int \frac{x + 1}{x} d x

\frac{d}{d x} (ln (arcsin (cos (x))))

\frac{d y}{d x} + 4 y = 11

\int \frac{( x ^{2} - 1 )}{x ^{\frac{3}{2}}} d x

\frac{d}{d x} (a - x)

What is the derivative of 2sec(x+cot(x)) ?
The derivative of 2sec(x+cot(x)) is 2sec(x)tan(x)-csc^2(x)
What is the first derivative of 2sec(x+cot(x)) ?
The first derivative of 2sec(x+cot(x)) is 2sec(x)tan(x)-csc^2(x)