What is the derivative of x+y+2 ?

The derivative of x+y+2 is (dy)/(dx)+1

What is the first derivative of x+y+2 ?

The first derivative of x+y+2 is (dy)/(dx)+1

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\frac{d}{d x} (x + y + 2)

\frac{d y}{d x} + 1

Solution steps

\frac{d}{d x} (x + y + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d y}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 + \frac{d y}{d x} + 0

Simplify

= \frac{d y}{d x} + 1

\int \frac{3 x ^{2} + 2 x + 4}{x ^{3} + 4 x} d x

\frac{d r}{d θ} + r tan (θ) = 3 tan (θ)

e^{5} + ln (7)

\int \frac{1}{3 x + 4} d x

y^{^{'}} + x y = a

What is the derivative of x+y+2 ?
The derivative of x+y+2 is (dy)/(dx)+1
What is the first derivative of x+y+2 ?
The first derivative of x+y+2 is (dy)/(dx)+1