What is the integral of (sqrt(y)) ?

The integral of (sqrt(y)) is 2/3 y^{3/2}+C

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integral of (sqrt(y))

\int (y) d y

\frac{2}{3} y^{\frac{3}{2}} + C

Solution steps

\int y d y

Apply the Power Rule

: \frac{2}{3} y^{\frac{3}{2}}

= \frac{2}{3} y^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} y^{\frac{3}{2}} + C

f (x) = e^{\frac{x}{3}}

y^{^{''}} - 8 y^{^{'}} + 25 y = 0

\frac{d}{d x} (\frac{2 x ^{2}}{x ^{2} - 1})

\frac{d}{d x} ((3 x^{2} - 5)^{3})

\frac{d}{d x} ((x + 8)^{\frac{2}{3}})