What is the limit as x approaches-1 of 1/(sqrt(x+1)) ?

The limit as x approaches-1 of 1/(sqrt(x+1)) is diverges

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limit as x approaches-1 of 1/(sqrt(x+1))

x \to - 1 lim (\frac{1}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

x \to - 1 - lim (\frac{1}{x + 1}) =

Undefined

= diverges

y^{^{''}} - y^{^{'}} + 4 y = 2 sin (2 t)

3 x \cdot ln (\frac{1}{x ^{2}})

\int_{4}^{\infty} x e^{- 5 x} d x

(y^{2} + x y^{2}) \frac{d y}{d x} = 1

x \to - 1 lim (\frac{4 x ^{2} + 1}{x})

What is the limit as x approaches-1 of 1/(sqrt(x+1)) ?
The limit as x approaches-1 of 1/(sqrt(x+1)) is diverges