What is the integral from 1 to 5 of 7/(x^2) ?

The integral from 1 to 5 of 7/(x^2) is 28/5

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integral from 1 to 5 of 7/(x^2)

\int_{1}^{5} \frac{7}{x ^{2}} d x

\frac{28}{5}

Decimal

5.6

Solution steps

\int_{1}^{5} \frac{7}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{5}

= 7 [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= 7 \cdot \frac{4}{5}

Simplify

= \frac{28}{5}

\frac{d}{d x} ((5 x + 8)^{3})

\frac{d}{d x} ((\frac{x - 7}{x + 2})^{2})

x^{\frac{1}{3}}, 1000

y = (x^{x} + 1)^{2}

\int 3 x^{2} (x^{3} + 5)^{7} d x

What is the integral from 1 to 5 of 7/(x^2) ?
The integral from 1 to 5 of 7/(x^2) is 28/5