What is the integral from 0 to 1.25 of 1250x ?

The integral from 0 to 1.25 of 1250x is 976.5625

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integral from 0 to 1.25 of 1250x

\int_{0}^{1.25} 1250 x d x

976.5625

Solution steps

\int_{0}^{1.25} 1250 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1250 \cdot \int_{0}^{1.25} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1.25}

= 1250 [\frac{x ^{2}}{2}]_{0}^{1.25}

Simplify

= 1250 [0.5 x^{2}]_{0}^{1.25}

Compute the boundaries:

0.78125

= 1250 \cdot 0.78125

Simplify

= 976.5625

\int \frac{16 x ^{3} - 32 x ^{2} + 7}{x ^{2} - 2 x} d x

4 δ (t) + 5 e^{t} - 5 e^{5 t}

y^{^{'}} = 0.06 (y - 65), y (0) = 190

f (t) = 10 cos (t)

x \to π lim (5 tan (x))

What is the integral from 0 to 1.25 of 1250x ?
The integral from 0 to 1.25 of 1250x is 976.5625