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Popular >

y^'-e^{8x+y}=0

Solution

y^{^{'}} - e^{8 x + y} = 0

Solution

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

Solution steps

y^{'} (x) - e^{8 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

Graph

Popular Examples

limit as x approaches 9 of x+8

x \to 9 lim (x + 8)

derivative of 1/(9x-1)

\frac{d}{d x} (\frac{1}{9 x - 1})

integral of 2x+yz

\int 2 x + yz d x

laplacetransform f(t)=6e^{-5t}+e^{3t}+5t^3-9 laplace transform

f (t) = 6 e^{- 5 t} + e^{3 t} + 5 t^{3} - 9

64y^{''}+16y^'+y=0

64 y^{^{''}} + 16 y^{^{'}} + y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'-e^{8x+y}=0 ?
The solution for y^'-e^{8x+y}=0 is y=-ln(-1/8 e^{8x}-c_{1})