What is the derivative of 7/(\sqrt[5]{x)} ?

The derivative of 7/(\sqrt[5]{x)} is -7/(5x^{6/5)}

What is the first derivative of 7/(\sqrt[5]{x)} ?

The first derivative of 7/(\sqrt[5]{x)} is -7/(5x^{6/5)}

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derivative of

\frac{7}{5 x}

- \frac{7}{5 x ^{\frac{6}{5}}}

Solution steps

\frac{d}{d x} (\frac{7}{5 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{5 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- \frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- \frac{1}{5} x^{- \frac{1}{5} - 1})

Simplify

7 (- \frac{1}{5} x^{- \frac{1}{5} - 1}) : - \frac{7}{5 x ^{\frac{6}{5}}}

= - \frac{7}{5 x ^{\frac{6}{5}}}

\frac{d}{d x} (x^{2} - 5 x + \frac{1}{x ^{\frac{3}{2}}})

\frac{d}{d x} (ln (x + 7))

\frac{d y}{d x} = 1 + 4 y^{2}

\int - 4 x (- 2 x^{2} + 2)^{5} d x

y = \frac{e ^{8 x}}{e ^{8 x} + 1}

What is the derivative of 7/(\sqrt[5]{x)} ?
The derivative of 7/(\sqrt[5]{x)} is -7/(5x^{6/5)}
What is the first derivative of 7/(\sqrt[5]{x)} ?
The first derivative of 7/(\sqrt[5]{x)} is -7/(5x^{6/5)}