What is inverse oflaplace (50)/(100+0.01s) ?

The answer to inverse oflaplace (50)/(100+0.01s) is 5000e^{-10000t}

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inverse oflaplace (50)/(100+0.01s)

inverse laplace

\frac{50}{100 + 0.01 s}

5000 e^{- 10000 t}

Solution steps

L^{- 1} {\frac{50}{100 + 0.01 s}}

= L^{- 1} {5000 \cdot \frac{1}{s + 10000}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 5000 L^{- 1} {\frac{1}{s + 10000}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 10000}} = e^{- 10000 t}

= 5000 e^{- 10000 t}

x \to 0 lim (\frac{1}{( x + 1 ) ^{2}})

(e^{x^{2} + 1})^{^{'}}

x^{3} os (x)

11 sin (t) + 14 cos (t)

\frac{d}{d x} (x^{2} + 4 x + 12 y - 8)

What is inverse oflaplace (50)/(100+0.01s) ?
The answer to inverse oflaplace (50)/(100+0.01s) is 5000e^{-10000t}