What is the tangent of 12-4e^x ?

The tangent of 12-4e^x is y=-4e^{a_{0}}x+12-4e^{a_{0}}+4a_{0}e^{a_{0}}

Popular >

tangent of 12-4e^x

tangent of

12 - 4 e^{x}

y = - 4 e^{a_{0}} x + 12 - 4 e^{a_{0}} + 4 a_{0} e^{a_{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 12 - 4 e^{a_{0}})

Find the slope of

y = 12 - 4 e^{x} : \frac{d y}{d x} = - 4 e^{x}

Compute the slope of

y = 12 - 4 e^{x}

x = a_{0} : m = - 4 e^{a_{0}}

Find the line with slope m=

- 4 e^{a_{0}}

and passing through

(a_{0}, 12 - 4 e^{a_{0}}) : y = - 4 e^{a_{0}} x + 12 - 4 e^{a_{0}} + 4 a_{0} e^{a_{0}}

y = - 4 e^{a_{0}} x + 12 - 4 e^{a_{0}} + 4 a_{0} e^{a_{0}}

\frac{\partial}{\partial x} (x^{x^{2} y})

\int \frac{5 x + 3}{x ^{2} + 4} d x

\int cos^{0} (x) d x

\frac{d}{d x} ((x - 2)^{3} e^{3 x})

\frac{\partial}{\partial z} (6 x y sin (z))

What is the tangent of 12-4e^x ?
The tangent of 12-4e^x is y=-4e^{a_{0}}x+12-4e^{a_{0}}+4a_{0}e^{a_{0}}