What is the integral of 3sec(x)(tan(x)-sec(x)) ?

The integral of 3sec(x)(tan(x)-sec(x)) is 3(sec(x)-tan(x))+C

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integral of 3sec(x)(tan(x)-sec(x))

\int 3 sec (x) (tan (x) - sec (x)) d x

3 (sec (x) - tan (x)) + C

Solution steps

\int 3 sec (x) (tan (x) - sec (x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int sec (x) (tan (x) - sec (x)) d x

Rewrite using trig identities

= 3 \cdot \int \frac{sin ( x ) - 1}{cos ^{2} ( x )} d x

Expand

\frac{sin ( x ) - 1}{cos ^{2} ( x )} : \frac{sin ( x )}{cos ^{2} ( x )} - \frac{1}{cos ^{2} ( x )}

= 3 \cdot \int \frac{sin ( x )}{cos ^{2} ( x )} - \frac{1}{cos ^{2} ( x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 (\int \frac{sin ( x )}{cos ^{2} ( x )} d x - \int \frac{1}{cos ^{2} ( x )} d x)

\int \frac{sin ( x )}{cos ^{2} ( x )} d x = sec (x)

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= 3 (sec (x) - tan (x))

Add a constant to the solution

= 3 (sec (x) - tan (x)) + C

g (t) = 3 t + 5

f (x) = \frac{6}{5 x + 2}

\frac{d}{d x} (e^{2 x} x^{3})

\int \frac{1}{9 x + 5} d x

\frac{\partial}{\partial x} (a x)

What is the integral of 3sec(x)(tan(x)-sec(x)) ?
The integral of 3sec(x)(tan(x)-sec(x)) is 3(sec(x)-tan(x))+C