sum from n=0 to infinity of 1/((n+1))

الحلّ

n = 0 \sum \infty \frac{1}{( n + 1 )}

يتباعد

خطوات الحلّ

n = 0 \sum \infty \frac{1}{n + 1}

Apply Series Limit Comparison Test:

يتباعد

= يتباعد

n = 1 \sum \infty \frac{n !}{n 7 ^{n}}

f (x) = 2 cos (3 x), at x = \frac{π}{2}

y = \frac{1}{2} x^{2}, (- 1, - 1)

\frac{d y}{d t} + 3 y = 1