What is the derivative of ln^2(2x) ?

The derivative of ln^2(2x) is (2ln(2x))/x

What is the first derivative of ln^2(2x) ?

The first derivative of ln^2(2x) is (2ln(2x))/x

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derivative of

ln^{2} (2 x)

\frac{2 ln ( 2 x )}{x}

Solution steps

\frac{d}{d x} (ln^{2} (2 x))

Apply the chain rule:

2 ln (2 x) \frac{d}{d x} (ln (2 x))

= 2 ln (2 x) \frac{d}{d x} (ln (2 x))

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

= 2 ln (2 x) \frac{1}{x}

Simplify

2 ln (2 x) \frac{1}{x} : \frac{2 ln ( 2 x )}{x}

= \frac{2 ln ( 2 x )}{x}

x \to 1 lim (\frac{∣ x - 1 ∣}{1 - x})

\frac{x ^{2} + 4 x + 3}{x}

\int \frac{1}{36 e ^{- 9 x} + e ^{9 x}} d x

\frac{\partial}{\partial y} (x - y)

f (x) = \frac{2}{5 x + 3}, at x = - 1

What is the derivative of ln^2(2x) ?
The derivative of ln^2(2x) is (2ln(2x))/x
What is the first derivative of ln^2(2x) ?
The first derivative of ln^2(2x) is (2ln(2x))/x