What is area y= 1/x ,y= 1/(x^2),y=4 ?

The answer to area y= 1/x ,y= 1/(x^2),y=4 is No Solution

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area y= 1/x ,y= 1/(x^2),y=4

area

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, y = 4

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{1}{x} = \frac{1}{x ^{2}} : x = 1

\frac{1}{x} = 4 : x = \frac{1}{4}

\frac{1}{x ^{2}} = 4 : x = \frac{1}{2}, x = - \frac{1}{2}

Curves not bounded

= No Solution

x \to + \frac{π}{2} lim (sec^{2} (x))

3 x^{2} + \frac{16 x}{3} - 2

f (x) = \frac{x}{x ^{2} + 3}

\frac{( z - 2 )}{z - 1}

y = 5 - 2 t

What is area y= 1/x ,y= 1/(x^2),y=4 ?
The answer to area y= 1/x ,y= 1/(x^2),y=4 is No Solution