What is the derivative of (13)/(x+1) ?

The derivative of (13)/(x+1) is -(13)/((x+1)^2)

What is the first derivative of (13)/(x+1) ?

The first derivative of (13)/(x+1) is -(13)/((x+1)^2)

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derivative of

\frac{13}{x + 1}

- \frac{13}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{13}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 13 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 13 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 13 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

13 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : - \frac{13}{( x + 1 ) ^{2}}

= - \frac{13}{( x + 1 ) ^{2}}

\int x^{6} x^{7} + 9 d x

ln (x^{3} sin^{2} (x))

\int \frac{6 x ^{2} - 11 x + 5}{3 x - 1} d x

\int_{- \infty}^{2} \frac{2}{x ^{2} + 4} d x

f (x) = 2 x - x^{2}

What is the derivative of (13)/(x+1) ?
The derivative of (13)/(x+1) is -(13)/((x+1)^2)
What is the first derivative of (13)/(x+1) ?
The first derivative of (13)/(x+1) is -(13)/((x+1)^2)