What is the limit as x approaches 2 of sqrt(2x^2+1) ?

The limit as x approaches 2 of sqrt(2x^2+1) is 3

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limit as x approaches 2 of sqrt(2x^2+1)

x \to 2 lim (2 x^{2} + 1)

3

Solution steps

x \to 2 lim (2 x^{2} + 1)

Plug in the value

x = 2

= 2 \cdot 2^{2} + 1

Simplify

2 \cdot 2^{2} + 1 : 3

= 3

- \frac{x + 3 arcsin ( x )}{4}

\int \frac{4 x - 10}{x ^{2} - 6 x + 8} d x

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f (t) = t^{6}

f (x) = 5 x^{4} - 5 x^{2} + 7

What is the limit as x approaches 2 of sqrt(2x^2+1) ?
The limit as x approaches 2 of sqrt(2x^2+1) is 3