What is the limit as x approaches 0 of ((sin(4x)))/x ?

The limit as x approaches 0 of ((sin(4x)))/x is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ((sin(4x)))/x

x \to 0 lim (\frac{( sin ( 4 x ) )}{x})

4

Solution steps

x \to 0 lim (\frac{sin ( 4 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 4 x ) \cdot 4}{1})

= x \to 0 lim (\frac{cos ( 4 x ) \cdot 4}{1})

Plug in the value

x = 0

= \frac{cos ( 4 \cdot 0 ) \cdot 4}{1}

Simplify

\frac{cos ( 4 \cdot 0 ) \cdot 4}{1} : 4

= 4

\int - 3 sin (5 x) cos^{2} (5 x) d x

x \to 0 lim (5 x)

f (x) = \frac{- 5}{x - 1}, at a = 8

r = 1 + cos (θ)

g (x) = (2 x^{2} + x + 9)^{- 3}

What is the limit as x approaches 0 of ((sin(4x)))/x ?
The limit as x approaches 0 of ((sin(4x)))/x is 4