What is the derivative of 2/(1+x) ?

The derivative of 2/(1+x) is -2/((1+x)^2)

What is the first derivative of 2/(1+x) ?

The first derivative of 2/(1+x) is -2/((1+x)^2)

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\frac{d}{d x} (\frac{2}{1 + x})

- \frac{2}{( 1 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{1 + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{1 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + x ) ^{2}} \frac{d}{d x} (1 + x)

= - \frac{1}{( 1 + x ) ^{2}} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= 2 (- \frac{1}{( 1 + x ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( 1 + x ) ^{2}} \cdot 1) : - \frac{2}{( 1 + x ) ^{2}}

= - \frac{2}{( 1 + x ) ^{2}}

\frac{d y}{d x} = \frac{4 x ^{3} + y ^{3}}{x y ^{2}}

\int_{x}^{1} 2 (x + y) d y

\frac{d ^{8}}{d x ^{8}} ((2 x + 5)^{7})

\frac{\partial}{\partial y} (2 x cos (y))

\int_{1}^{4} - x^{2} + 5 x - 4 d x

What is the derivative of 2/(1+x) ?
The derivative of 2/(1+x) is -2/((1+x)^2)
What is the first derivative of 2/(1+x) ?
The first derivative of 2/(1+x) is -2/((1+x)^2)