What is the solution for y^'=((e^x))/y ?

The solution for y^'=((e^x))/y is y=sqrt(2e^x+c_{1)},y=-sqrt(2e^x+c_{1)}

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y^'=((e^x))/y

y^{^{'}} = \frac{( e ^{x} )}{y}

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

Solution steps

y^{'} (x) = \frac{( e ^{x} )}{y}

Solve separable ODE:

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

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What is the solution for y^'=((e^x))/y ?
The solution for y^'=((e^x))/y is y=sqrt(2e^x+c_{1)},y=-sqrt(2e^x+c_{1)}