What is the derivative of (95t)/(99t-95) ?

The derivative of (95t)/(99t-95) is -(9025)/((99t-95)^2)

What is the first derivative of (95t)/(99t-95) ?

The first derivative of (95t)/(99t-95) is -(9025)/((99t-95)^2)

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derivative of

\frac{95 t}{99 t - 95}

- \frac{9025}{( 99 t - 95 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{95 t}{99 t - 95})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 95 \frac{d}{d t} (\frac{t}{99 t - 95})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 95 \cdot \frac{\frac{d t}{d t} ( 99 t - 95 ) - \frac{d}{d t} ( 99 t - 95 ) t}{( 99 t - 95 ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} (99 t - 95) = 99

= 95 \cdot \frac{1 \cdot ( 99 t - 95 ) - 99 t}{( 99 t - 95 ) ^{2}}

Simplify

95 \cdot \frac{1 \cdot ( 99 t - 95 ) - 99 t}{( 99 t - 95 ) ^{2}} : - \frac{9025}{( 99 t - 95 ) ^{2}}

= - \frac{9025}{( 99 t - 95 ) ^{2}}

\int \frac{2 x}{x ^{2} + 100} d x

x \to 2 lim (2 x - 5)

\int \frac{- 6000}{( 3 x + 50 ) ^{2}} d x

\int \frac{2 x - 1}{x ( x ^{2} + 3 x + 2 )} d x

2 \frac{d y}{d t} + y = 0

What is the derivative of (95t)/(99t-95) ?
The derivative of (95t)/(99t-95) is -(9025)/((99t-95)^2)
What is the first derivative of (95t)/(99t-95) ?
The first derivative of (95t)/(99t-95) is -(9025)/((99t-95)^2)