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Popular >

integral of cos(6θ)

Solution

\int cos (6 θ) d θ

Solution

\frac{1}{6} sin (6 θ) + C

Solution steps

\int cos (6 θ) d θ

Apply u-substitution

: \int cos (u) \frac{1}{6} d u

= \int cos (u) \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{6} sin (u)

Substitute back

u = 6 θ

= \frac{1}{6} sin (6 θ)

Add a constant to the solution

= \frac{1}{6} sin (6 θ) + C

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x \to \frac{1}{5} lim (\frac{x}{( 10 x - 2 )})

integral of 1/((x^2+3)^2)

\int \frac{1}{( x ^{2} + 3 ) ^{2}} d x

derivative of (x^2/((x+1)^2))

\frac{d}{d x} (\frac{x ^{2}}{( x + 1 ) ^{2}})

(\partial)/(\partial x)(3xe^{-3xy})

\frac{\partial}{\partial x} (3 x e^{- 3 x y})

integral of 5(2x-1)^4

\int 5 (2 x - 1)^{4} d x

Frequently Asked Questions (FAQ)

What is the integral of cos(6θ) ?
The integral of cos(6θ) is 1/6 sin(6θ)+C