What is the integral from-1 to 0 of x^2 ?

The integral from-1 to 0 of x^2 is 1/3

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integral from-1 to 0 of x^2

\int_{- 1}^{0} x^{2} d x

\frac{1}{3}

Solution steps

\int_{- 1}^{0} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{0}

= [\frac{x ^{3}}{3}]_{- 1}^{0}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\int e^{c o s (8 x)} sin (8 x) d x

x \to 1 lim ((x - 1) (x + 1))

\frac{d}{d x} (\frac{1}{cos ( x )})

x \to 0 lim (x e^{x})

\frac{d}{d x} ((\frac{x - 5}{2 x + 1})^{3})

What is the integral from-1 to 0 of x^2 ?
The integral from-1 to 0 of x^2 is 1/3