What is the derivative of (x+4x)(x^{3/2}-x) ?

The derivative of (x+4x)(x^{3/2}-x) is (5(5x^{3/2}-4x))/2

What is the first derivative of (x+4x)(x^{3/2}-x) ?

The first derivative of (x+4x)(x^{3/2}-x) is (5(5x^{3/2}-4x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(x + 4 x) (x^{\frac{3}{2}} - x)

\frac{5 ( 5 x ^{\frac{3}{2}} - 4 x )}{2}

Solution steps

\frac{d}{d x} ((x + 4 x) (x^{\frac{3}{2}} - x))

Simplify

(x + 4 x) (x^{\frac{3}{2}} - x) : 5 x (x^{\frac{3}{2}} - x)

= \frac{d}{d x} (5 x (x^{\frac{3}{2}} - x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (x (x^{\frac{3}{2}} - x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{\frac{3}{2}} - x

= 5 (\frac{d x}{d x} (x^{\frac{3}{2}} - x) + \frac{d}{d x} (x^{\frac{3}{2}} - x) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{\frac{3}{2}} - x) = \frac{3 x ^{\frac{1}{2}}}{2} - 1

= 5 (1 \cdot (x^{\frac{3}{2}} - x) + (\frac{3 x ^{\frac{1}{2}}}{2} - 1) x)

Simplify

5 (1 \cdot (x^{\frac{3}{2}} - x) + (\frac{3 x ^{\frac{1}{2}}}{2} - 1) x) : \frac{5 ( 5 x ^{\frac{3}{2}} - 4 x )}{2}

= \frac{5 ( 5 x ^{\frac{3}{2}} - 4 x )}{2}

y = ln ∣ sec (x) + tan (x) ∣

\frac{d}{d x} (\frac{4 sin ( x )}{3 + cos ( x )})

\frac{\partial}{\partial x} (x e^{- z})

\frac{\partial}{\partial x} (x^{2} ln (y))

\frac{( 3 s + 3 )}{( s ^{2} ( s + 2 ) ^{3} )}

What is the derivative of (x+4x)(x^{3/2}-x) ?
The derivative of (x+4x)(x^{3/2}-x) is (5(5x^{3/2}-4x))/2
What is the first derivative of (x+4x)(x^{3/2}-x) ?
The first derivative of (x+4x)(x^{3/2}-x) is (5(5x^{3/2}-4x))/2