What is ydy=(2x)/((1+x^2))dx,y(0)=2 ?

The solution to ydy=(2x)/((1+x^2))dx,y(0)=2 is No Solution

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ydy=(2x)/((1+x^2))dx,y(0)=2

y d y = \frac{2 x}{( 1 + x ^{2} )} d x, y (0) = 2

No Solution

Solution steps

[y d y = \frac{2 x}{( 1 + x ^{2} )} d x y (0) = 2]

Solve

y (0) = 2 :

No Solution

No Solution

\frac{\partial}{\partial y} (3 x^{3 y})

\int (5 x - 4)^{2} d x

f (x) = (3 x + 5)^{3}

f (x) = \frac{5}{x + 2}

y = 4 x^{2}, y = x^{2} + 1

What is ydy=(2x)/((1+x^2))dx,y(0)=2 ?
The solution to ydy=(2x)/((1+x^2))dx,y(0)=2 is No Solution